A statistics professor gives a surprising quiz consisting of 10 true/false questions and states that passing r

A statistics professor gives a surprising quiz consisting of 10 true/false questions and states that passing requires 6 correct responses. Assume that an unprepared student adopts the questionable strategy of guessing for each answer.


Find the probability that the first 6 responses are correct and the last 4 are wrong.A statistics professor gives a surprising quiz consisting of 10 true/false questions and states that passing r
As others have said, the probability that the first 6 are correct and the last 4 are wrong is 1/2^10 = 1/1024.





This is much smaller than the probability of passing by guessing, because there are many other ways in which you can get 6 correct questions and 4 incorrect ones; and you could also get 7, 8, 9 or 10 questions correct by guessing. Therefore (a) is correct and (b) and (c) are wrong.A statistics professor gives a surprising quiz consisting of 10 true/false questions and states that passing r
c
The chance that out of:


(T/F)(T/F)(T/F)(T/F)(T/F)(T/F)(T/F)(T/鈥?br>

You get


(T)(T)(T)(T)(T)(T)(F)(F)(F)(F)


Guessing on each problem is merely:


(1/2)^10


or .0009765624


Essentially, there are 2^10 possible results, and TTTTTTFFFF is one of them. Another way to thing of this is 1/(2^10) which is also .0009765624.
1/(2)^10 = 1/1024


as I understand the question
Id like to use my lifeline phone-a-friend.......wtf is this Q about again???????????